"The Length Of A Rectangle Is 2cm Less Than Twice Its Width. What Is Its Width In Cm, If Its Perimeter Is 50cm?"
The length of a rectangle is 2cm less than twice its width. What is its width in cm, if its perimeter is 50cm?
Answer:
The width of the rectangle is 9cm.
Step-by-step explanation:
Let x be the width
Let 2x -2 be the length
Formula: P = 2(l + w)
Solution:
P = 2(l + w)
50 = 2(2x - 2 + x)
50 = 2(2x+x - 2)
50 = 2(3x -2)
50 = 6x -4
-6x = -4 -50
-6x = -54
-6x = -54 (division property of equality)
-6 -6
x = 9
x = 9, the value of the width
2x - 2 = 2(9) -2 = 18 - 2 = 16, the value of the length
We can check if the answer is correct.
Checking:
P = 2(l + w)
50 = 2(16 + 9)
50 = 2(25)
50 = 50
Therefore, the width of the rectangle is 9cm.
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