"The Length Of A Rectangle Is 2cm Less Than Twice Its Width. What Is Its Width In Cm, If Its Perimeter Is 50cm?"

The length of a rectangle is 2cm less than twice its width. What is its width in cm, if its perimeter is 50cm?

 

Answer:

The width of the rectangle is 9cm.

Step-by-step explanation:

Let x be the width

Let 2x -2 be the length

Formula: P = 2(l + w)

Solution:

P = 2(l + w)

50 = 2(2x - 2 + x)

50 = 2(2x+x - 2)

50 = 2(3x -2)

50 = 6x -4

-6x = -4 -50

-6x = -54

-6x = -54    (division property of equality)

-6      -6

x = 9

x = 9, the value of the width

2x - 2 = 2(9) -2 = 18 - 2 = 16, the value of the length

We can check if the answer is correct.

Checking:

P = 2(l + w)

50 = 2(16 + 9)

50 = 2(25)

50 = 50

Therefore, the width of the rectangle is 9cm.